
Originally Posted by
Mutley
This may answer your question on why the car will not start after running out of fuel. If you put the key in and turn it immediately the pump will be unable to deliver enough fuel to purge the system so will not start at all, what you need to do is just turn on the ignition and leave it for at least a minute in order to purge the lines,( removing the relay and jumping the terminals has the same effect, as you found out) a more detailed explanation may help you below.
The Motronic electrical system is controlled by a single system relay with dual contacts. A permanent voltage supply is made to relay terminals 30 and 86 from the battery positive terminal. When the ignition is switched on, the ECU earths terminal 85 through ECU terminal number 36 which energises the first relay winding. This causes the first relay contacts to close and terminal 30 is connected to the output circuit at terminal 87. A voltage supply is thus output at terminal 87. Terminal 87 supplies voltage to the injectors, ECU terminal 37, ISCV and the FTVV when fitted. In addition voltage is supplied to the second relay contact. When the ignition is switched on. the ECU briefly earths relay contact 85b at ECU terminal 3. This energises the second relay winding, which closes the second relay contact and connects voltage from terminal 30 to terminal 87b, thereby providing voltage to the fuel pump circuit. After approximately one second, the ECU opens the circuit and the pump stops. This brief running of the fuel pump allows pressure to build within the fuel pressure lines, and provides for an easier start The second circuit will then remain open until the engine is cranked or run. Once the ECU receives a speed signal from the CAS, the second winding will again be energised by the ECU, and the fuel pump will run until the engine is stopped.