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Thread: OT: Calculus Challenge of the day.

  1. #1
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    Default OT: Calculus Challenge of the day.

    So, here's today's Assignment for you guys to solve.


    There is a very strong radiation source in the center of a large 120 x 120 foot room. A person must run through this room to get to safety. Her escape route takes her the full lenth along one wall of the room. She is not exposed to radiation outside the room. The strength of the radiation is inversely proprtional to the square of her distance from the source. At 5- feet, her body is absorbing radiation at the rate of 200 un**** per second. If she runs at 12 feet per second, what is the tottal radiation dose she recieves during her dash to safety?


    You must show the integral used to solve problem.

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  2. #2
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    Default Enough to cook a bowl of ramen

    and heat a cup of green tea


    Vee ave vays of dealing vid your kind...........

  3. #3
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    haha...cmon, where are the mechanical/civil engineers on the board?

    www.KaRealtySF.com
    Build Date: 05-1995 /Engine: m50tu /Automatic Transmission /ABS /NO ASC /Open Differential /EAT Chip

  4. #4
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    Oy! Yer just trying to get someone to do your homework assignment for you, aren't you?

  5. #5
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    Not DO it...just HELP. hahaha.

    www.KaRealtySF.com
    Build Date: 05-1995 /Engine: m50tu /Automatic Transmission /ABS /NO ASC /Open Differential /EAT Chip

  6. #6
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    Yes there are mech engineers on the board, but speaking for myself i finished university so that i would never have to do stuff like that again......... but I'll see what i can come up with

    Germans: Why can't they make everything?

  7. #7
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    okay dokey
    R = rate of rad absorption (units/sec)
    x = distance from the source (feet)
    k = constant

    now R = k/(x^2)
    so 200 units/s = k/(5^2)
    therefore k = 5000

    now in order to solve this you need to find the total units of rad she absorbed

    so that will be the Integral of R with respect to time

    you will need to find an expression for the distance with respect to time.
    that is to say x= f(t)
    probably some kind of parabola
    then you will find the Integral of k/(x^2) with respect to time
    ie integral of 5000/(f(t)^2) with respect to time

    you bastard, the horrible memories are flowing back...... nooooooo

    edit: the expression for x is something like x = sqrt((60-ut)^2+60^2)
    where sqrt is the square root and u is the chick's velocity
    Last edited by rob101; 03-15-2006 at 08:23 PM.

    Germans: Why can't they make everything?

  8. #8
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    Default

    10.9 units




    Quote Originally Posted by liquidtiger720
    So, here's today's Assignment for you guys to solve.


    There is a very strong radiation source in the center of a large 120 x 120 foot room. A person must run through this room to get to safety. Her escape route takes her the full lenth along one wall of the room. She is not exposed to radiation outside the room. The strength of the radiation is inversely proprtional to the square of her distance from the source. At 5- feet, her body is absorbing radiation at the rate of 200 un**** per second. If she runs at 12 feet per second, what is the tottal radiation dose she recieves during her dash to safety?


    You must show the integral used to solve problem.
    Last edited by Bellicose Right Winger; 03-15-2006 at 08:22 PM.
    .....Got to keep the loonies on the paath.

  9. #9
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    i just noticed a type while going through the proble....5- is suppose ot be 50. But I think I can manage. Thank you everybody for the well needed boost. Rob and Bellicose, you deserve a cookie!.


    sorry to bring back bad memories rob!
    Last edited by liquidtiger720; 03-15-2006 at 08:35 PM.

    www.KaRealtySF.com
    Build Date: 05-1995 /Engine: m50tu /Automatic Transmission /ABS /NO ASC /Open Differential /EAT Chip

  10. #10
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    integral is "*&*^%%^$(]}@{" - without the ""s
    the answer is 6
    95 E34 530I V2.37
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