OT: Calculus Challenge of the day.

[GoldenEagleFan]

Remember back to your grade scholol days and you wondered how could math ever be practical.....

When you're bored in class remember....Lots of calculus used in designing engines and autos.

For example...

Calculus is the foundation for camshaft design. As a camshaft lobe rotates, the valve lifts or returns. This rate of change of distance with respect to time is dx/dt or velocity. Differentiate again and you dv/dt or acceleration. To fast of acceleration and valves separate from followers or impact their seats too hard. The acceleration rates determine the spring pack you need to keep the system stable. Too high of rate of spring and you can get excessive force on the cam lobe leading to premature wear. On and on and on. All based off of calculus!

[rob101]

at 12 feet a second it will take the lady 10 seconds to cross the room. At any given instance in time she is a certain distance from the center of the room. This distance can be calculated by Pythagreons theorom. For instance, at time =0 she is the square root of 60^2+60^2 at from the center. at time =5 seconds she is 60 feet from the center. At time=x she is the square root of (60-12*t)^2 (t=time in seconds)+60^2. Take this equation, then use the fact that at 50ft the absorbtion rate is given, use the info that the rate is inversly proportional to the distance and integrate with respect to time from 0-5 and multiply your answer by two.

okay, step back for a second
its not that hard, I will post something to you over PM. I have to look up bearings for a crane right now!

[632 Regal]

all BS that doesnt need to have a certificate in.

Remember back to your grade scholol days and you wondered how could math ever be practical.....

When you're bored in class remember....Lots of calculus used in designing engines and autos.

For example...

Calculus is the foundation for camshaft design. As a camshaft lobe rotates, the valve lifts or returns. This rate of change of distance with respect to time is dx/dt or velocity. Differentiate again and you dv/dt or acceleration. To fast of acceleration and valves separate from followers or impact their seats too hard. The acceleration rates determine the spring pack you need to keep the system stable. Too high of rate of spring and you can get excessive force on the cam lobe leading to premature wear. On and on and on. All based off of calculus!

[liquidtiger720]

all BS that doesnt need to have a certificate in.

I see them wanting me to take calculus as: learn how to critically think around problems that you will have in the future. So, its not exactly just the math bs.

[GoldenEagleFan]

Didn't mean to imply you needed a certificate to design cams.. just giving an example of how calculus could be used and something to think about while siting bored in the class room.

[liquidtiger720]

Didn't mean to imply you needed a certificate to design cams.. just giving an example of how calculus could be used and something to think about while siting bored in the class room.

I don't think i'm ever bored in my calculus class actually...the material is hard for me, so it keeps me entertained.

[Andrem5]

Let us get to the most relevant question: Why are your Throwing Stars on backwards??

okay dokey
R = rate of rad absorption (units/sec)
x = distance from the source (feet)
k = constant

now R = k/(x^2)
so 200 units/s = k/(5^2)
therefore k = 5000

now in order to solve this you need to find the total units of rad she absorbed

so that will be the Integral of R with respect to time

you will need to find an expression for the distance with respect to time.
that is to say x= f(t)
probably some kind of parabola
then you will find the Integral of k/(x^2) with respect to time
ie integral of 5000/(f(t)^2) with respect to time

you bastard, the horrible memories are flowing back...... nooooooo

edit: the expression for x is something like x = sqrt((60-ut)^2+60^2)
where sqrt is the square root and u is the chick's velocity

[rob101]

Let us get to the most relevant question: Why are your Throwing Stars on backwards??

because a typical retardo frigging used car salesman idiot put them on that way....... are they seriously backwards?
typical my friend brought over this car that'd been roadworthied lately, brakes were faaaaaaaarked, i mean i've never seen brakes that have pitted from corrosion and kickback violently when he brakes not to mention it didn't really brake past a certain point, this car was as roadworthy as a streetluge i could know that from being in the passenger's seat. typical used car ********, most people who give roadworthys here are crooks who don't even look at the carsunless you aren't a dealer then they make it really hard to get one..
lesson is...... used car salesmen are scum who should be exterminated, and that is why they are on backwards. no offensive to any used car people from outside australia, this is not directed at you, but if you are a used car dealer from australia go and kill yourself please now, thank you.

[Andrem5]

because a typical retardo frigging used car salesman idiot put them on that way....... are they seriously backwards?

Yeah, it happens. You always have to remind tire monkeys about that.

If you decide to flip them it is recommended that you replace the OE "triple square" aluminum bolts with something that won't corrode. I used stainless hex bolts and applied anti-sieze.

[onewhippedpuppy]

Try this, disclaimer, I hate Calculus. You're dealing with a triangle, 60ft from the center to the wall, 60 ft along the wall to the edge of the room. As the lady moves from 60 ft to 0 ft (center), the hypotenuse of the triangle represents her distance from the source. So, the distance from the source is sqrt (60^2 + x^2). At 5 ft, the strength is 200, so a constant over the distance equals 200. Your time is a constant because her velocity is constant. 60 ft to the middle / 12 ft/sec = 5 sec, or 10 sec across the room. However, the strength varies with x, so you need to integrate the strength with respect to x, then multiply it by the time. Since we're using the triangle it's only half the room, so the result must be multiplied by 2. Maybe this helps, somebody check my work.