OT: Calculus Challenge of the day.

[rob101]

Nah they're not all bad memories, I have to deal with politics at work which is waaaaaaaaaaaaaaaaay worse.

what are you studying anyway?

[liquidtiger720]

does this sound right?


500,000/24 * S(1/((60-x)^2)+60^2) dx

S = integral with range 0 to 60.



I'm a business finance major. I have no clue why they want me to take 1.5 years of calculus. I'm hardly up to the task. This is calc 2, and I'm already struggling.

[Bellicose Right Winger]

No problem. That makes it 100x the dose so 1091 units.

My numerical integration is rusty, so be sure you tell us the REAL answer.

i just noticed a type while going through the proble....5- is suppose ot be 50. But I think I can manage. Thank you everybody for the well needed boost. Rob and Bellicose, you deserve a cookie!.


sorry to bring back bad memories rob!

[Bellicose Right Winger]

0-60? I integrated over the 10 seconds it takes to run the distance.

does this sound right?


500,000/24 * S(1/((60-x)^2)+60^2) dx

S = integral with range 0 to 60.



I'm a business finance major. I have no clue why they want me to take 1.5 years of calculus. I'm hardly up to the task. This is calc 2, and I'm already struggling.

[rob101]

0-60? I integrated over the 10 seconds it takes to run the distance.

yeah you need to integrate over time not distance, so S dt not S dx.

business and calculus? the business people in this country can't even use Excel when they graduate...... hehe

[liquidtiger720]

lol...the above shows why I shouldn't be in this class.

[GoldenEagleFan]

at 12 feet a second it will take the lady 10 seconds to cross the room. At any given instance in time she is a certain distance from the center of the room. This distance can be calculated by Pythagreons theorom. For instance, at time =0 she is the square root of 60^2+60^2 at from the center. at time =5 seconds she is 60 feet from the center. At time=x she is the square root of (60-12*t)^2 (t=time in seconds)+60^2. Take this equation, then use the fact that at 50ft the absorbtion rate is given, use the info that the rate is inversly proportional to the distance and integrate with respect to time from 0-5 and multiply your answer by two.

[bahnstormer]

cant remeber the last time i did hw....
soph year i think =\

[632 Regal]

no I figured it out again, answer is 6.

[liquidtiger720]

im lost now.